🔴 The Error You're Seeing
Confirm this matches your console output. If it does, you're in the right place.
org.springframework.web.client.HttpClientErrorException$BadRequest: 400 Bad Request: "{"error": "Invalid email format"}"
at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:68)
at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:104)⚡ Quick Fix Works 80% of the time
Log the exact request body you are sending to the external API and compare it to their documentation.
log.info("Sending payload: {}", requestBody);
restTemplate.postForObject(url, requestBody, String.class);🧠 Why this Happens
Tap to expand the deep technical explanation
Your Spring Boot app used `RestTemplate` or `WebClient` to send a POST/PUT request to an external API. The external server read your payload, found it invalid (missing fields, wrong format), and responded with a 400 Bad Request. Spring translated this into an exception.
The HITEC City Parking Spot Analogy:
It's like mailing a package with the wrong customs declaration form. The border patrol (external API) inspects it, sees the form is invalid, and sends the package back to you (400 Bad Request).
🔁 How to Reproduce Confirm this is your error
Use `RestTemplate` to POST `{"email": "null"}` to an API that strictly requires a valid email string. The API will return 400, and RestTemplate will throw the exception.
🛠️ Solutions (5 Ways to Fix)
Log the outgoing request body
👉 Use this to debug exactly what you are sending.
Print the JSON payload right before sending it to verify its structure.
ObjectMapper mapper = new ObjectMapper();
String json = mapper.writeValueAsString(userRequest);
log.info("Outgoing JSON: {}", json);
restTemplate.postForObject(url, userRequest, String.class);Intercept the full response body
👉 Use this to see the exact error message from the external server.
The exception contains the response body. Extract it to see why the external API rejected the request.
try {
restTemplate.postForObject(url, req, String.class);
} catch (HttpClientErrorException e) {
String responseBody = e.getResponseBodyAsString();
log.error("External API error: {}", responseBody);
}Fix Content-Type header
👉 Use this if you are sending JSON but the header is set to text/plain.
The external API expects JSON, but your client might be sending the wrong Content-Type header.
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<UserRequest> entity = new HttpEntity<>(req, headers);
restTemplate.postForObject(url, entity, String.class);Fix serialization issues (e.g., null fields)
👉 Use this if the external API requires fields that your object is sending as null.
Ensure your DTO is populated correctly before sending. Use @JsonInclude to control nulls.
@JsonInclude(JsonInclude.Include.NON_NULL)
public class UserRequest {
private String email; // Ensure this isn't null
}Use WebClient for better error handling
👉 Use this if you want reactive, declarative error handling.
WebClient's onStatus method is much cleaner for handling 4xx/5xx errors than RestTemplate's try-catch.
webClient.post().uri(url)
.bodyValue(req)
.retrieve()
.onStatus(HttpStatusCode::is4xxClientError, response -> response.bodyToMono(String.class).map(Exception::new))
.bodyToMono(String.class)
.block();📋 Version Notes
Throws HttpClientErrorException.
Throws HttpClientErrorException, but WebClient is preferred for new apps.
🛡️ How to Prevent This Next Time
Always write integration tests for external API calls using MockWebServer to ensure your payload matches their expected format exactly.